1.

Find the heat needed to convert 10g of ice at 0 celsius to water at 20 celsius.Given: Latent heat of fusion of ice= j/kg; specific heat of water= 4200 J/kg-k.

Answer»

10g=0.01kgFor converting 0 DEGREES ice to 0 DEGREE water the amount of heat isQ=mlf=0.01*336000=3360For converting 0 degrees water to 20 degrees water isQ=mass*SPECIFIC heat*TEMPARATURE difference=0.01*4200*(20-0)=840Total heat =3360+840=4200



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