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InterviewSolution
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Find the height from the surface of the moon where the value of 'g' is equal to the value of 'g' at a height of 57,600 km from the surface of the Earth. (Take, mass of the Earth, M_(E) = 6 xx 10^(24) kg, Mass of the moon, M_(m) = 7.3 xx 10^(22) kg, radius of the Earth, R_(E) = 6400 and radius of the moon, R_(m) = 1740 km) |
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Answer» Solution :(i) (1.) The VALUE of acceleration due to GRAVITY at a height 'h' is given by, `g^(1)` `= (GM_(m))/((R + h)^(2))` (2.) The value of `g^(1)` is equal height `h_(E)` from the SURFACE of the EARTH `h_(m)` from the surface of the moon. `rArr g^(1) = (GM_(E))/((R_(E) + h_(E))^(2)) = (GM_(m))/((R_(m) + h_(E))^(2))` Substitute the values of `M_(E), M_(m), R_(E), h_(E), R_(m)` and find the value of `h_(m)` from equation (2). (ii) 5300 km |
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