1.

Find the height of the point vertically above theearth's surface at which the acceleration due togravity becomes 1% of its value at the surfacein terms of R. (R is the radius of the earth)

Answer»

gh=gR^2/(R+h)^2

given

gH=g/100

Therefore we have

gR^2/(R+h)^2=g/100

or R+h=10R

or h=9R



Discussion

No Comment Found

Related InterviewSolutions