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Find the HPBW of the uniform rectangular aperture antenna with 4λ×2λ in the E-plane?(a) 0.443(b) 0.886(c) 0.25(d) 0.5This question was posed to me in an internship interview.My question is from Aperture Antenna topic in portion Aperture Antenna of Antennas |
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Answer» CORRECT CHOICE is (a) 0.443 The best I can EXPLAIN: HPBW = 2 arcsin\((\frac{0.443\lambda}{B})\)≈0.886λ/b=0.886/2=0.443. |
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