1.

The first null beam width in the E-plane of a rectangular aperture of a×b is given by _______________(a) 2sin^-1⁡(λ/b)(b) sin^-1⁡(λ/a)(c) 2sec^-1⁡(λ/b)(d) 2cos^-1⁡(λ/a)The question was posed to me in an online quiz.My question is taken from Aperture Antenna in chapter Aperture Antenna of Antennas

Answer» CORRECT answer is (a) 2sin^-1⁡(λ/b)

To explain I would say: The area the power is radiated is GIVEN by Beam-width. The beam-width between the FIRST nulls is the FNBW. \(\frac{KB}{2}\) sinθ=nπ

θ= sin^-1\(⁡(\frac{n\LAMBDA}{b})\)

Therefore, the FNBW in E-plane is given by FNBW=2 θ = sin^-1⁡\(⁡(\frac{\lambda}{b})\).


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