InterviewSolution
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InterviewSolution
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Find the increment of the free energy of the surface layer when two identical mercury droplets, each of diameter `d = 1.5 mm`, merge isothermally. |
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Answer» When two mercury drops each of diameter `d` merge, the resulting drop has diameter `d_1` where `(pi)/(6) d_1^3 = (pi)/(6) d^3 xx 2` or, `d_1 = 2^(1//3) d` The increase in free energy is `Delta F = pi 2^(2//3) d^2 alpha-2 pi d^2 alpha = 2pid^2 alpha(2^(-1//3) -1) = - 1.43 mu J`. |
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