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Find the indicated terms in each of the following arithmetic progression:1, 6, 11, 16, ..., t16, |
Answer» Given: 1, 6, 11, 16, … Here, a = 1 d = a2 – a1 = 6 – 1 = 5 and n = 16 We have, tn = a + (n – 1)d So, t16 = 1 + (16 – 1)5 = 1 + 15×5 t16 = 1 +75 t16 = 76 |
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