1.

Find the initial velocity of a car which is stopped in 10seconds by applying brakes . Theretardation due to brakes is 2.5 ms-2.​

Answer»

Answer:

25 m/s

Explanation:

Given:

  • Time TAKEN = t = 10 seconds
  • Acceleration = a = -2.5 m/s²
  • Final velocity = v = 0 m/s

To find:

  • Initial velocity = u

Using the first equation of motion:

V=u+at

0=u+ -2.5×10

0=u -25

u=0+25

u=25 m/s

The initial velocity of the car is EQUAL to 25 m/s

More:

  • Second equation of motion = s=ut+1/2 at²
  • Third equation of motion = v²-u²=2as
  • Distance TRAVELLED in NTH second equation of motion = sn = u+a/2(2n-1)
  • Average speed = total distance/total time
  • Average velocity = total displacement / total time


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