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Find the linear factors of `x^(2)-5xy+4y^(2)+x+2y-2` |
Answer» Given expression is `x^(2)-5xy+4y^(2)x+2y-2`………………I Its corresponding equation is `x^(2)-5xy+4y^(2)+x+2y-2=0` or `x^(2)-x(5y-1)+4y^(2)+2y-2=0` `:.x=((5y-1)+-sqrt((5y-1)^(2)-4.1.(4y^(2)+2y-2)))/2` `=((5y-1)+-sqrt((9y^(2)-18y+9))/2` `=((5y-1)+-sqrt((3y-3)^(2))/2` `=((5y-1)+-(3y-3))/2=4y-2,y+1` `:.` The required linear factors are `(x-4y+z)` and `(x-y-1)`. |
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