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Find the mass of 1.5 moles of CaCO_(3). |
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Answer» Solution :Molar mass of `CaCO_(3) = 40 + 12 + (3 XX 16)` = `40 + 12 xx 48` = 100 g Mass = `"molar mass" xx "NUMBER of moles"` = `100 xx 1.5` = 150 g The mass of 1.5 moles of `CaCO_(3)` = 150 g. |
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