1.

Find the mass of 1.5 moles of CaCO_(3).

Answer»

Solution :Molar mass of `CaCO_(3) = 40 + 12 + (3 XX 16)`
= `40 + 12 xx 48` = 100 g
Mass = `"molar mass" xx "NUMBER of moles"`
= `100 xx 1.5` = 150 g
The mass of 1.5 moles of `CaCO_(3)` = 150 g.


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