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Find the moment of inertia of a solid cylinder of mass M and radius R about a line parallel to the axis of the cylinder and on the surface of the cylinder. |
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Answer» The moment of inertia of the cylinder about is axis is `(MR^(2))/2`. Using parallel axis theorem. `I=I_(0)+MR^(2)=(MR^(2))/2+MR^(2)=3/2MR^(2)` Similarly the moment of inertia of a solid sphere about a tangent is `2/3 MR^(2)+MR^(2)=7/5MR^(2)` |
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