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Find the order and degree of the following differential equations.(i) dy/dx + 2 y = x3(ii) d3y/dx3 + 3(dy/dx)3 + 2(dy/dx) = 0(iii) d2y/dx2 = √(y - dy/dx)(iv) d3y/dx3 = 0 |
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Answer» (i) dy/dx + 2 y = x3 Highest order derivative is dy/dx power of dy/dx is 1 ∴ order = 1 Degree = 1 (ii) d3y/dx3 + 3(dy/dx)3 + 2(dy/dx) = 0 Highest order derivative is d3y/dx3 Power of d3y/dx3 = 1 ∴ order = 3 Degree = 1 (iii) d2y/dx2 = √(y - dy/dx) Here we eliminate the radical sign. squaring both sides we get, (d2y/dx2)2 = (y - dy/dx) ∴ order = 2 Degree = 2 (iv) d3y/dx3 = 0 order = 3, Degree = 1 |
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