1.

Find the order and degree of the following differential equations.(i) dy/dx + 2 y = x3(ii) d3y/dx3  + 3(dy/dx)3 + 2(dy/dx) = 0(iii) d2y/dx2 = √(y - dy/dx)(iv) d3y/dx3 = 0

Answer»

(i) dy/dx + 2 y = x3

Highest order derivative is dy/dx

power of dy/dx is 1

∴ order = 1    Degree = 1

(ii) d3y/dx + 3(dy/dx)+ 2(dy/dx) = 0

Highest order derivative is d3y/dx3

Power of d3y/dx3  = 1

∴ order = 3    Degree = 1

(iii) d2y/dx= √(y - dy/dx)

Here we eliminate the radical sign. squaring both sides we get,

(d2y/dx2)2  = (y - dy/dx)

∴ order = 2    Degree = 2

(iv) d3y/dx= 0

order = 3,     Degree = 1



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