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Find the perimeter of the triangle formed by the points (0,0),(1,0),(0,1) ​

Answer»

According to this question: Let the points be A(0,0), B(1,0)& C(0,1) ⚫The distance between two points ALWAYS taken as positive. Using the formula of distance between two points: =) AB= √(0-1)² + (0-0)² =) AB = √1 + 0 =) AB =√1 =) AB= 1 BC= √(1-0)² + (0-1)² =) BC= √1 + 1 =) BC = √2 CA = √(0-0)² +(1-0)² =) CA= √0 + 1 =) CA = √1 =) CA = 1 Therefore, We know that perimeter of triangle is; Side + side + side =) AB + BC + AC =) 1 + √2 + 1 =) 2+ √2 Hence, The perimeter of ∆ is 2+√2. EXPLANATION:hope u have been understood mark me as brainlist



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