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Find the `pH` of solution prepared by mixing `25 ml` of a `0.5 M` solution of `HCl, 10 ml` of a `0.5 M` solution of `NaOH` and `15 ml` of waterA. `0.8239`B. `1.0029`C. `1.0239`D. `1.8239` |
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Answer» Correct Answer - A We know that for `HCl` and `NaOH`, m.e.`=`milli`-`equivalent ` :. M.e.` of `HCl=0.5xx25=12.5` `m.e.` of `NaOH=0.5xx10=5.0` `m.e.` of `HCl` in the resultant mixture `=12.5-5.0=7.5` Total volume `=(25+10+15)ml=50ml` `:.` Normality of `HCl=(m.e)/(Vol(ml))=(7.50)/(50)` ` :.` Molarity `=(7.50)/(50)` `:. =[H^(+)]=[HCl]=(7.50)/(50)` `:. pH= -log(7.50)/(50)=0.8239` |
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