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Find the point on x-axis which is equidistant from the points (- 2, 5) and (2,- 3). |
Answer» Points A(-2, 5) and B(2, -3) are equidistant from point P. Let the coordinates of point are P(x, 0) Using distance formula = \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\) ⇒ PA = PB \(\sqrt{(x + 2)^2 + (0- 5)^2}\) = \(\sqrt{(x - 2)^2 + (0+ 3)^2}\) On squaring both sides, we get (x + 2)2 + (0 - 5)2 = (x - 2)2 + (0 + 3)2 x2 + 4x + 4 + 25 = x2 - 4x + 4 + 9 8x = - 16x = -2 Hence, coordinates are (- 2, 0). |
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