1.

Find the point where the line `(x-1)/2=(y-2)/-3=(z+3)/4` meets the plane `2x+4y-z=1`.A. (3,-1,1)B. (3,1,1)C. (1,1,3)D. (1,3,1)

Answer» Correct Answer - A
Let point be (a , b , c) then
2a + 4b - c = 1 `" " …. (i)`
and a = 2k + 1 , b = -3k + 2 and c = 4k - 3
(where k is constant )
On substituting these values in Eq. (i) , we get
2(2k + 1) + 4(-3 k + 2)- (4k - 3) = 1
`implies k = 1`
Hence , required point is (3 , -1 , 1) .


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