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Find the power available if overall efficiency of plant is 80%, flow rate is 4.42cumecs and head 400m?(a) 6.52MW(b) 8.18MW(c) 11.255MW(d) 13.875MWI had been asked this question in my homework.I want to ask this question from Hydrographs topic in chapter Hydro Electric Power Plant of Energy Engineering

Answer»

Right CHOICE is (d) 13.875MW

For EXPLANATION I would say: Power AVAILABLE:

P = wQHno X 10^-3 KW

= 9810 X 4.42 X 400 X 0.8 X 10^-6 MW

P = 13.875MW.



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