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Find the pressure at the tip of a drawing pin on area `0.2 mm` square if it is pushed against a board with a force of 5 kg wt. (use `g=10m//s^(2))` |
Answer» Here, `A = 0.2 mm sq` `=0.2 xx 0.2 sq mm = 0.04 xx 10^(-6)m^(2)` `F=5 kg wt = 5 xx 10 N` Pressure ,`P=F/A = (5 xx 10)/(0.04 xx 10^(-6))=1.25 xx 10^(9) Pa`. |
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