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Find the principalvalue of `tan^(-1){sin(-pi/2)}`A. `(pi)/(4)`B. `-(pi)/(4)`C. `(3pi)/(4)`D. `(3pi)/(4)` |
Answer» We know that sin`-(pi)/(2)=-1` `therefore tan^(-1){sin(-pi)/(2)}=tan^(-1)(-1)=-(pi)/(2)` |
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