

InterviewSolution
Saved Bookmarks
1. |
Find the range of `f(x)=x^2-x-3.` |
Answer» Correct Answer - `[-13//4, infty)` `f(x) = x^(2) - x - 3 (x - (1)/(2))^(2) - (1)/(4) - 3 = (x - (1)/(2))^(2)-(13)/(4)` ` (x - (1)/(2))^(2 )ge 0, AA x in` R ` (x - (1)/(2))^(2 )-(13)/(4)ge (-13)/(4), AA x in`R Hence, the range is `[13//4. infty)`. |
|