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                                    Find the roots of the quadratic equations by using the quadratic formula in each of the following `2x^(2)-3x-5=0` | 
                            
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Answer» Given equation is `2x^(2)-3x-5=0` On comparing with `ax^(2)+bx+c=0` we get `a=2,b=-3` and `c=-5` By quadratic formula `x=(-b+1sqrt(b^(2)-4ac))/(2a)` `=(-(-3)+-sqrt((-3)^(2)-4(2)(-5)))/(2(2))=(3+-sqrt(9+40))/4` `=(3+-sqrt(49))/4=(3+-7)/4=10/4 . (-4)/4=5/2 . -1` So `5/2` and `-1` are the roots of the given equation.  | 
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