InterviewSolution
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Find the separate equation of the lines represented by the following equation :(x – 2)2 – 3(x – 2)(y + 1) + 2(y + 1)2 = 0 |
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Answer» (x – 2)2 – 3(x – 2)(y + 1) + 2(y + 1)2 = 0 ∴ (x – 2)2 – 2(x – 2)(y + 1) – (x – 2)(y + 1) + 2(y + 1)2 = 0 ∴ (x – 2) [(x – 2) – 2(y + 1)] – (y + 1)[(x – 2) – 2(y + 1)] = 0 ∴ (x – 2)(x – 2 – 2y – 2) – (y + 1)(x – 2 – 2y – 2) = 0 ∴ (x – 2)(x – 2y – 4) – (y + 1)(x – 2y – 4) = 0 ∴ (x – 2y – 4)(x – 2 – y – 1) = 0 ∴ (x – 2y – 4)(x – y – 3) = 0 ∴ the separate equations of the lines are x – 2y – 4 = 0 and x – y – 3 = 0. Alternative Method : (x – 2)2 – 3(x – 2)(y + 1) + 2(y + 1)2 = 0 … (1) Put x – 2 = X and y + 1 = Y ∴ (1) becomes, X2 – 3XY + 2Y2 = 0 ∴ X2 – 2XY – XY + 2Y2 = 0 ∴ X(X – 2Y) – Y(X – 2Y) = 0 ∴ (X – 2Y)(X – Y) = 0 ∴ the separate equations of the lines are ∴ X – 2Y = 0 and X – Y = 0 ∴ (x – 2) – 2(y + 1) = 0 and (x – 2) – (y +1) = 0 ∴ x – 2y – 4 = 0 and x – y – 3 = 0. |
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