1.

Find the size nature and position of imageformed when an object of size 1 cm is atdistance of 15 cm from a Concave mirror of focallength 10 cm.​

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Answer:

Hey!!

The given MIRROR is a concave mirror thus sign convention it's focal LENGTH will be negative.

This here

f = -10 cm

u = -15cm

h(height of object) = 1cm

we have to find

size , nature , position of image formed .

Thus using mirror equation :-

1/f = 1/u+1/v

=>1/v = 1/f-1/u

=> 1/v = -1/10+1/15

=> 1/v = -1/30

=> v = -30 { thus image will be formed BEYOND center

Now magnification

m = -(v/u) = h'/h

m = -(-30/-15)

=> m = -2

HENCE the image formed will be real and INVERTED and magnified.

Now m = h'/h

2 = h'/1

=> h' = 2cm

hence the size of the image will be doubled


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