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Find the solution set of –3 < x – 2 ≤ 9 – 2x ; x ∈ Z (set of integers). |
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Answer» – 3 < x – 2 < 9 – 2x ⇒ – 3 < x – 2 and x – 2 < 9 – 2x ⇒ – 3 + 2 < x and x + 2x < 9 + 2 ⇒ – 1 < x and 3x < 11 or x < \(\frac{11}{3}\) ⇒ − 1 < \(x\) ≤ \(\frac{11}{3}\) Since \(x\) ∈ Z, so the solution set = {0, 1, 2, 3}. |
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