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Find the sum `(2+4+6+8+…+100).` |
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Answer» Correct Answer - 2550 We know that `(1+2+3+…+n)=(1)/(2)n(n+1).` `therefore (2+4+6+8+...+100)=2xx(1+2+3+...+50)=(2xx(1)/(2)xx50xx51)=2550.` |
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