1.

Find the sum of first 1000 positive integers.

Answer»

Given A.P.

1, 2, 3, 4, 5 …….. 1000

First term (a) = 1

Common difference (d) = 2 – 1 = 1

Last term (l) = 1000

Formula, Sn = n/2(a + l)

S1000 = 1000/2 (1 + 1000)

= 500 × 1001 = 500500

Hence, sum of first 1000 positive integers.

= 500500



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