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Find the sum of first 20 terms of an A.P. whose nth term is given by Tn = (7 - 3n).(A) 382(B) -490(C) 420(D) -382 |
Answer» The correct option is: (B) -490 Explanation: We have, Tn = (7 -3n) First term, T1 = (7 -3 x 1) = 4 Second term, T2 = 7 - 3 x 2= 1 Third term, T3 = 7 -3 x 3 = -2 .'. Series is 4, 1, - 2, .......... and common difference = -3 Sum of first 20 terms (S20) = 20/2[2 x 4 + (20 - 1)(-3)] = 10[8 - 57] = -490 |
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