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Find the sum of first 22 terms of an A.P. in which d = 22 and a22 = 149. |
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Answer» a22= a + 21d 149 = a + 21(22) a = 149 – 462 a = -313 S22 = \(\frac{22}{2}\) [2a + (22 - 1)d] = 11 [-626 + 462] = 11 (-164) = -1804 |
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