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Find the sum of first n even natural numbers. |
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Answer» First n even natural numbers: 2, 4, 6, 8, 10,….,n Here, a = 2, d = 4 – 2 = 2 Sum = Sn = n/2 [2a + (n-1)d] = n/2 [2(2) + (n-1)(2)] = n(n+1) |
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