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Find the sum of first n natural numbers. |
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Answer» First n natural numbers: 1, 2, 3, 4, 5, …, n Here, a = 1, d = 1 Sum = Sn = n/2 [2a + (n-1)d] = n/2 [2(1) + (n-1)(1)] = n(n+1)/2 |
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