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Find the sum of the following AP:0.6, 1.7, 2.8,…, to 100 terms. |
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Answer» Given A.P : 0.6, 1.7, 2.8,…. S100 a = 0.6; d = a2 – a1 = 1.7 – 0.6 = 1.1; n = 100 Sn = \(\frac{n}{2}\) [2a + (n – 1)d] ∴ S100 = \(\frac{100 }{2}\) [2 × 0.6 + (100 – 1)1.1] = 50 [1.2 + 99 × 1.1] = 50 [1.2 + 108.9] = 50 × 110.1 = 5505 |
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