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Find the sum of the following AP:2, 7, 12,…, to 10 terms. |
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Answer» Given A.P: 2, 7, 12, …… to 10 terms a = 2; d = a2 – a1 = 7 – 2 = 5; n = 10 Sn = \(\frac{n}{2}\) [2a + (n – 1)d] ∴ S10 = \(\frac{10}{2}\) [2 × 2 + (10 – 1)5] = 5 [4 + 9 × 5] = 5 [4 + 45] = 5 × 49 = 245 |
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