1.

Find the sum of the following AP:2, 7, 12,…, to 10 terms.

Answer»

Given A.P: 2, 7, 12, …… to 10 terms 

a = 2; d = a2 – a1 = 7 – 2 = 5; n = 10 

Sn\(\frac{n}{2}\) [2a + (n – 1)d] 

∴ S10 = \(\frac{10}{2}\) [2 × 2 + (10 – 1)5] 

= 5 [4 + 9 × 5] 

= 5 [4 + 45]

= 5 × 49 

= 245



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