Find the sum of the following arithmetic progressions : 41, 36, 31, �

1.	Find the sum of the following arithmetic progressions : 41, 36, 31, … to 12 terms
Answer» For the given AP the first term a is 41, and common difference d is a difference of the second term and first term, which is 36 - 41 = - 5 To find : the sum of given AP The formula for sum of AP is given by, s = \(\frac{n}{2}\)(2a + (n - 1)d) Substituting the values in the above formula, s = \(\frac{12}{2}\)(82 + (11)(-5)) s = 6 × 27 s = 162

Find the sum of the following arithmetic progressions : 41, 36, 31, … to 12 terms

Answer»

For the given AP the first term a is 41, and common difference d is a difference of the second term and first term, which is 36 - 41 = - 5

To find : the sum of given AP

The formula for sum of AP is given by,

s = \(\frac{n}{2}\)(2a + (n - 1)d)

Substituting the values in the above formula,

s = \(\frac{12}{2}\)(82 + (11)(-5))

s = 6 × 27

s = 162