1.

Find the sum of the following arithmetic progressions :3,9/2,6,15/2,....to 25 terms

Answer»

For the given AP the first term a is 3, and common difference d is a difference of the second term and first term, which is 9/2-3 = 3/2.

To find : the sum of given AP 

The formula for sum of AP is given by,

s = \(\frac{n}{2}\)(2a + (n - 1)d

Substituting the values in the above formula,

s = \(\frac{25}{2}\)(6 + (24)(\(\frac{3}{2}\)))

s = 25 × 21 

s = 525



Discussion

No Comment Found