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Find the sum of the following arithmetic progressions :3,9/2,6,15/2,....to 25 terms |
Answer» For the given AP the first term a is 3, and common difference d is a difference of the second term and first term, which is 9/2-3 = 3/2. To find : the sum of given AP The formula for sum of AP is given by, s = \(\frac{n}{2}\)(2a + (n - 1)d Substituting the values in the above formula, s = \(\frac{25}{2}\)(6 + (24)(\(\frac{3}{2}\))) s = 25 × 21 s = 525 |
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