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Find the sum of the following arithmetic progressions: 50, 46, 42, …. To 10 terms |
Answer» For the given AP the first term a is 50, and common difference d is a difference of second term and first term, which is 46 - 50 = - 4 To find : The sum of given AP The formula for sum of AP is given by s = \(\frac{n}{2}\)(2a + (n-1)d) Substituting the values in the above formula, s = \(\frac{10}{2}\)(100 + (9)(-4)) s = 5 × 64 s = 320 |
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