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Find the sum of the following arithmetic progressions : 1, 3, 5, 7, … to 12 terms |
Answer» For the given AP the first term a is 1, and common difference d is a difference of the second term and first term, which is 3 - 1 = 2 To find : The sum of given AP The formula for sum of AP is given by, s = \(\frac{n}{2}\)(2a + (n-1)d) Substituting the values in the above formula, s = \(\frac{12}{2}\)(2+(11)(2)) s = 6 × 24 s = 144 |
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