1.

Find the sum of the following arithmetic progressions : 1, 3, 5, 7, … to 12 terms

Answer»

For the given AP the first term a is 1, and common difference d is a difference of the second term and first term, which is 3 - 1 = 2 

To find : The sum of given AP 

The formula for sum of AP is given by,

s = \(\frac{n}{2}\)(2a + (n-1)d)

Substituting the values in the above formula,

s = \(\frac{12}{2}\)(2+(11)(2))

s = 6 × 24 

s = 144



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