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Find the sum of the following geometric progressions : 1,3,9,27,.... to 8 terms |
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Answer» Common Ratio = r = \(\frac{3}{1}\) = 3 \(\therefore\) Sum of GP for n terms = \(\frac{a(r^n -1)}{r-1}\)..... (1) ⇒ a = 1, r = 3, n = 8 ∴ Substituting the above values in (1) we get ⇒ \(\frac{1(3^8 -1)}{3-1}\) ⇒ \(\frac{3^8 -1}{2}\) ⇒ 3280 |
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