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Find the sum of the following geometric progressions : 1, -1/2,1/4,-1/8 |
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Answer» Common Ratio = r = \(\frac{\frac{-1}{2}}{1}\) = \(\frac{-1}{2}\) ∴ Sum of GP till infinity = \(\frac{a}{1-r}\) ........ (1) ⇒ a = 1, r = \(\frac{-1}{2}\) ∴ Substituting the above values in (1), we get, ⇒ \(\frac{1}{1-(\frac{-1}{2})}\) ⇒ \(\frac{1}{\frac{3}{2}}\) ⇒ \(\frac{2}{3}\) |
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