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Find the sum of the following series to `n`term: `2^3+4^3+6^3+8^3+ ` |
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Answer» Correct Answer - `2n^(2)(n+1)^(2)` `T_(n)={2+(n-1)xx2}^(3)=(2n)^(3)=8n^(3)` `therefore S_(n)=8{sum_(k=1)^(n)k^(3)}=8xx(1)/(4)n^(2)(n+1)^(2)=2n^(2)(n+1)^(2).` |
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