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Find the sum of the series whose nth term is given by: ` (3n^(2)-3n+2)` |
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Answer» Correct Answer - `2n(n^(2)+1)` `T_(n)=(3n^(2)-3n+2).` `therefore S_(n)=3(sum_(k=1)^(n)k^(2))-3(sum_(k=1)^(n)k)+2n " "[because 2+2+2+.. "n times" = 2n]`. |
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