Find the surface area of a cuboid whose(i) length = 10 cm, breadth = 1

1.	Find the surface area of a cuboid whose(i) length = 10 cm, breadth = 12 cm, height = 14 cm(ii) length = 6 dm, breadth = 8 dm, height = 10 dm(iii) length = 2m, breadth = 4 m, height = 5 m(iv) length = 3.2 m, breadth = 30 dm, height = 250 cm.
Answer» (i) Given, Length = 10 cm Breadth = 12 cm Height = 14 cm So, Surface area of cuboid = 2(lb x bh x hl) = 2(10 x 12 + 12 x 14 + 14 x 10) = 2(120 + 168 + 140) = 2 x 428 = 856 cm² (ii) Given, Length = 6 dm Breadth = 8 dm Height = 10 dm So, Surface area of cuboid = 2(lb x bh x lh) = 2(6 x 8 + 8 x 10 + 10 x 6) 2(48 + 80 + 60) = 2 x 188 = 376 dm² (iii) Given, Length = 2 m Breadth = 4 m Height = 5 m So, Surface area of cuboid = 2(lb x bh x lh) = 2(2 x 4 + 4 x 5 + 5 x 2) = 2(8 + 20 + 10) = 2 x 38 = 76 m² (iv) Given, length = 3.2 m= 32 dm breadth = 30 dm height = 250 cm= 25 dm so, surface area of cuboid = 2(lb x bh x lh) = 2(32 x 30 + 30 x 25 + 25 x 32) = 2(960 + 750 + 800) = 2 x 2510 = 5020 dm²

Find the surface area of a cuboid whose(i) length = 10 cm, breadth = 12 cm, height = 14 cm(ii) length = 6 dm, breadth = 8 dm, height = 10 dm(iii) length = 2m, breadth = 4 m, height = 5 m(iv) length = 3.2 m, breadth = 30 dm, height = 250 cm.

Answer»

(i) Given,

Length = 10 cm

Breadth = 12 cm

Height = 14 cm

So,

Surface area of cuboid = 2(lb x bh x hl) = 2(10 x 12 + 12 x 14 + 14 x 10)

= 2(120 + 168 + 140) = 2 x 428 = 856 cm²

(ii) Given,

Length = 6 dm

Breadth = 8 dm

Height = 10 dm

So,

Surface area of cuboid = 2(lb x bh x lh) = 2(6 x 8 + 8 x 10 + 10 x 6)

2(48 + 80 + 60) = 2 x 188 = 376 dm²

(iii) Given,

Length = 2 m

Breadth = 4 m

Height = 5 m

So,

Surface area of cuboid = 2(lb x bh x lh) = 2(2 x 4 + 4 x 5 + 5 x 2)

= 2(8 + 20 + 10) = 2 x 38 = 76 m²

(iv) Given,

length = 3.2 m= 32 dm

breadth = 30 dm

height = 250 cm= 25 dm

so,

surface area of cuboid = 2(lb x bh x lh) = 2(32 x 30 + 30 x 25 + 25 x 32)

= 2(960 + 750 + 800) = 2 x 2510 = 5020 dm²