1.

Find the tangent to the curve y=5x^4-3x^2+2x-1 at x=1.(a) 15(b) 14(c) 16(d) 17I had been asked this question at a job interview.Asked question is from Derivatives Application in portion Application of Derivatives of Mathematics – Class 12

Answer»

Right answer is (C) 16

Easiest explanation: The SLOPE of the TANGENT at x=1 is given by

\(\frac{dy}{dx}\)]x=1= 20x^3-6x+2]x=1=20(1)^3-6(1)+2=20-6+2=16



Discussion

No Comment Found

Related InterviewSolutions