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Find the time constant in a series R-L circuit when the resistance is 4 ohm and the inductance is 2 H.(a) 0.25(b) 0.2(c) 2(d) 0.5This question was addressed to me in an interview.The doubt is from Resistances and Capacitances topic in chapter Electrostatic Boundary Value Problem of Electromagnetic Theory

Answer»

Correct answer is (d) 0.5

Explanation: The time constant for an R-L series CIRCUIT will be τ = L/R. Put R = 4 and L = 2. We GET τ = 2/4 = 0.5 second.



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