1.

Find the torque of a force 7i+3j-5k about the origin.The force acts on a particle whose position vector is

Answer»

Torqueis defined as→τ=→r×→F(→ris the position vector and→Fis the force vector)

So, here→τ=(i−j+k)×(7i+3j−5k)=(2i+12j+10k)

So,∣∣→τ∣∣=√4+144+100=√248=15.74N.m



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