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Find the two numbers whose A.M. is 25 and GM is 20. |
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Answer» Given: A.M = 25, G.M = 20. G.M = √ab A.M = (a + b)/2 So, √ab = 20 ……. (1) (a + b)/2 = 25……. (2) a + b = 50 a = 50 – b Putting the value of ‘a’ in equation (1), we get, √[(50 - b)b] = 20 b2 – 50b + 400 = 0 b2 – 40b – 10b + 400 = 0 b(b – 40) – 10(b – 40) = 0 b = 40 or b = 10 If b = 40 then a = 10 If b = 10 then a = 40 ∴ The numbers are 10 and 40. |
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