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Find the two-thirds life `(t_(2//3))` of a first order reaction in which `k=5.48xx10^(-1) "sec"^(-1) ` ( log 3 = 0.4771 , log 2 = 0.3010) |
Answer» Correct Answer - 2.0005 s `(t_(2//3))=(2.303)/(k)log_(10).(a)/(a-(2)/(3)a)` |
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