1.

Find the value of (4i)×(-6i)​

Answer»

!! Hey Mate !! your answer is -- LET, A = 4i^ and B = (-6k^) we can WRITE it as A = 4i^ + 0j^ + 0K^ and B = 0i^ +0j^ - 6k^ such that , a1 = 4 , a2=0, a3=0 and b1 = 0 , b2 = 0 , b3= -6 we know that , A × B = i^(a2b3-b2a3) - j^(a1b3-b1a3) +k^(a1b2-b1a2) => A×B = i^(0×-6-0×4)-j^(4×-6-0×0)+k^(4×0-0×0) => A×B = i^(0) - j^(-24) +k^(0) => A×B = 24j^Explanation:



Discussion

No Comment Found

Related InterviewSolutions