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Find the value of a,b,c,d if \(\begin{bmatrix}a+b&c\\a-b&2c+d\end{bmatrix}\)=\(\begin{bmatrix}3&2\\1&6\end{bmatrix}\).(a) 3, 2, 1, 4(b) 3, 2, 1, 6(c) 2, 2, 2, 2(d) 2, 1, 2, 2The question was asked during an interview for a job.Origin of the question is Types of Matrices in section Matrices of Mathematics – Class 12

Answer»

The correct choice is (d) 2, 1, 2, 2

To ELABORATE: The two matrices \(\BEGIN{BMATRIX}a+b&c\\a-b&2c+d\end{bmatrix}\)and\(\begin{bmatrix}3&2\\1&6\end{bmatrix}\) are equal matrices. Comparing the two matrices, we get

a-b=3, c=2, a-b=1, 2c+d=6

Solving the above equations, we get a=2, b=1, c=2, d=2.



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