1.

Find the value of cot x - tan x1). 2cot 2x2). sec x3). cosec x4). 3cot x

Answer»

$(\cot x - \tan x = \;\FRAC{{\cos x}}{{\SIN x}} - \frac{{\sin x}}{{\cos x}})$

= $(\frac{{co{s^2}x - SI{n^2}x}}{{\sin x\;cos\;x}})$

= $(\frac{{2cos2x}}{{2\sin x\;cos\;x}})$

= $(2 \times \frac{{\cos 2x}}{{\sin 2x}} = 2\cot 2x)$



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