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Find the value of k for which of (7, -2), (5, 1), (3, k) are collinearA) -4B) 4C) -5D) 5 |
Answer» Correct option is (B) 4 Given that points (7, -2), (5, 1), (3, k) are collinear. \(\therefore\) Area of formed triangle is zero. \(\therefore\frac12|7(1-k)+5(k-(-2))+3(-2-1)|=0\) \(\Rightarrow|7-7k+5k+10-9|=0\) \(\Rightarrow|-2k+8|=0\) \(\Rightarrow-2k+8=0\) \(\Rightarrow2k=8\) \(\Rightarrow k=\frac82=4\) Correct option is B) 4 |
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